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iVinArrow [24]
3 years ago
13

Given the function f(x) = The quantity of 4x minus 2, divided by 3, which of the below expressions is correct

Mathematics
2 answers:
jarptica [38.1K]3 years ago
6 0

Answer:

f^{-1}(x)=\text{The quantity of 3x plus 2, divided by 4}

Step-by-step explanation:

Given,

f(x) = The quantity of 4x minus 2, divided by 3,

\implies f(x) = \frac{4x-2}{3} -----(1)

Since, f^{-1}(x) represents the inverse of f(x),

Also, for finding the inverse of a function f(x) we follow the following steps,

Step 1 : Replace f(x) by y,

Step 2 : Interchange x and y,

Step 3 : Isolate y in the left side of the equation,

Step 4 : Replace y by f^{-1}(x)

Now, from equation (1),

y=\frac{4x-2}{3}

By interchanging x and y,

x=\frac{4y-2}{3}

3x = 4y - 2

-4y = -2 - 3x \implies y = \frac{3x+2}{4}

By replacing y by f^{-1}(x)

f^{-1}(x)=\frac{3x+2}{4}

\implies f^{-1}(x)=\text{The quantity of 3x plus 2, divided by 4}

Drupady [299]3 years ago
5 0

Answer:

f^-1(x) = The quantity of 3x plus 2, divided by 4.

Step-by-step explanation:

Given: f(x) = (4x -2)/3

Which is y = (4x - 2)/3

We have to find the inverse function f^-1 (x)

Replace x by y and y by x, we get

x = (4y - 2)/3

Now find the function y interms of x.

3x = 4y - 2

4y = 3x + 2

y = (3x + 2)/4

f^-1(x) = The quantity of 3x + 2, divided by 4.

Answer is D) f^-1(x) = The quantity of 3x plus 2, divided by 4.

Hope this will helpful.

Thank you.

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Answer:

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Step-by-step explanation:

When two polygons are congruent, it implies that they have the same shape and size. Therefore, their corresponding angles and sides are congruent to each other.

When naming congruent polygons, the arrangement of the vertices are kept in a definite order of arrangement.

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DR corresponds to SL

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We can select any two out of these sets of corresponding angles and sides as our answer. Thus:

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Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

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