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Sonja [21]
2 years ago
5

An organization advocating for healthcare reform has estimated the average cost of providing healthcare for a senior citizen rec

eiving Medicare to be about $13,000 per year. The article also stated that, with 90% confidence, the margin or error for the estimate is $1,000. Determine the resulting 90% confidence interval for the average cost for healthcare of a senior citizen receiving Medicare.
Mathematics
1 answer:
asambeis [7]2 years ago
7 0

Using the definition of a confidence interval, it is found that the 90% confidence interval for the average cost for healthcare of a senior citizen receiving Medicare is ($12,000, $14,000).

A confidence interval is the <u>sample mean plus/minus the margin of error</u>.

  • In this problem, the sample mean is of $13,000.
  • The margin of error is of $1,000.

Hence:

$13,000 - $1,000 = $13,000

$13,000 + $1,000 = $14,000

The interval is ($12,000, $14,000).

A similar problem is given at brainly.com/question/24869727

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Answer:

<h2>8.3 in²</h2>

Step-by-step explanation:

We have

three triangles with the base <em>b = 2 in.</em> and the height <em>h₁ = 2.2 in.</em>

one triangle with the base <em>b = 2 in. </em>and the height <em>h₂ = 1.7 in.</em>

The formula of an area of a triangle:

A=\dfrac{b\cdot h}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

Substitute:

A_1=\dfrac{(2)(2.2)}{2}=\dfrac{4.4}{2}=2.2\ in^2

A_2=\dfrac{(2)(1.7)}{2}=1.7\ in^2

S.A.=3A_1+A_2

S.A.=3(2.2)+1.7=6.6+1.7=8.3\ in^2

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