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Lynna [10]
2 years ago
7

A cone has a volume of 1,256 cubic centimeters. If the height of the cone is 12 centimeters, what is the radius of the base in c

entimeters?
Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

Answer:

The radius 10 cm

Step-by-step explanation:

∵ The volume of the cone = 1/3 πr²h

∵ v = 1256 cm³

∵ h = 12 cm

∴ 1256 = 1/3 π (12) r²

∴ r² = 1256 × 3/12π = 100 cm

∴ r = √100 = 10 cm

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When we make inferences about the difference of two independent population proportions, what assumptions do we need to make? mar
Elis [28]

When we make inferences about the difference of two independent population proportions, we assume that it is a random sample, and the number of successes and failures are at least 15 in each group.

Two independent proportions tests involve comparing the proportions of two unrelated datasets.

For these two datasets to be regarded as an independent population, the following must be true or assumed to be true

  • The datasets must represent a random sample
  • Each dataset must contain at least 15 successes and failures

Hence, the above highlights are the assumptions of two independent population proportions.

To learn more about independent populations from the given link

brainly.com/question/23989150

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4 0
1 year ago
Please help i'd really appreciate it.
BlackZzzverrR [31]
The answer is
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8 0
3 years ago
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a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Show the working out too please in numbers, thank you.
vazorg [7]

Hii :))

\tt \: - 5 =  \frac{x}{6}  \\   \tt \:  - 5 \times 6 = x \\  \boxed{  \tt \:  - 30 = x}

__________________

  • The correct value of x is <u>-</u><u> </u><u>3</u><u>0</u><u>.</u>

\overbrace{ \underbrace{ \sf \: \infty  \:  Carry \: on \: Learning \:  \infty }}

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0
2 years ago
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In a trapezoid the sum of the bases is 28 and the area is 84.
oee [108]

Answer:   If you sketch this out, you should be able to convince yourself that if you drew a line parallel to the bases and halfway between them, and a vertical at the end of that line, there would be an extra triangle on the longer base that would just fit into the space at the end of the shorter base, if you cut and pasted it.

You should also be able to convince yourself by what you know about similarity that the length of that parallel halfway line is just halfway between the lengths of the bases (you can add them and divide by two).

So your trapezoid (trapezium, we call ’em this side of the pond) has the same area as a rectangle with an altitude equal to the trapezoid’s and a width equal to the sum of those bases divided by two. And since you know about rectangles, you’re home and dry. I suggest you do the sketch, fill in the numbers, and then you’ve completed a model piece of homework that should earn full marks and the teacher’s approval.

Step-by-step explanation:

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