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2 years ago

Solve for x: 2(x+5)=4+6

Mathematics

1 answer:

arsen [322]2 years ago

8 0

Answer:

$x=0$

Step-by-step explanation:

First distribute:

$2(x+5)=4+6\\\\2x+10=4+6$

Then simplify:

$2x=0\\x=0$

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Solve for x (-4/3) x - 6 = -26 A. −27 B. −15 C. 15 D. 27

andre [41]

$- \dfrac{4}{3} x - 6 = -26$

//Add 6 to both sides:
$- \dfrac{4}{3} x = -20$

//Multiply by -1 on both sides:
$\dfrac{4}{3} x = 20$

Multiply by 3 on both sides:
$4x = 60$

Divide by 4 on both sides:
$x = 15$

-----------------------------------------
Answer: x = 15 (Answer C)
-----------------------------------------

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3 years ago

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kozerog [31]

Answer:

Step-by-step explanation:

Any number that have the | | symbol will automatically be positive

For example

| -5.8 | = 5.8

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3 years ago

The radius of a circle is 7m , find its area in terms of π

dangina [55]

Answer:

49π

Step-by-step explanation:

A = π $r^{2}$

A = π $7^{2}$

A = 49π

For the one you put in the comment...

The radius of a circle is 19cm find its area in terms of π

A = π $r^{2}$

A = π 1 $9^{2}$

A = 361π

For the other one you put in the comment

The radius of a circle is 4 cm find its area in terms of π

A = π $r^{2}$

A = π $4^{2}$

A = 16π

For the other one you put in the comment

The radius of a circle is 20 cm find its area in terms of π

A = π $r^{2}$

A = π $20^{2}$

A = 400π

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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3 years ago

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What is the value of x in the equation 58 = 10x − 2?

solong [7]

Answer:

Step-by-step explanation:

10x6=60-2=58

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3 years ago

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Find the intersection points using substitution or elimination for each system of equations:

natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

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3 years ago