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Luden [163]
3 years ago
9

a chord of 12cm long of 8cm is away from the of the circle what is the lenght of the chord which is 6cm away from the centre

Mathematics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

The length of the chord is 16 cm

Step-by-step explanation:

Mathematically, a line from the center of the circle to a chord divides the chord into 2 equal portions

From the first part of the question, we can get the radius of the circle

The radius form the hypotenuse, the two-portions of the chord (12/2 = 6 cm) and the distance from the center to the chord forms the other side of the triangle

Thus, by Pythagoras’ theorem; the square of the hypotenuse equals the sum of the squares of the two other sides

Thus,

r^2 = 8^2 + 6^2

r^2= 64 + 36

r^2 = 100

r = 10 cm

Now, we want to get a chord length which is 6 cm away from the circle center

let the half-portion that forms the right triangle be c

Using Pythagoras’ theorem;

10^2 = 6^2 + c^2

c^2 = 100-36

c^2 = 64

c = 8

The full

length of the chord is 2 * 8 = 16 cm

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Find the distance between two points ( -1,1) and (2,-4)
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The distance between two points ( -1,1) and (2,-4) is:

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Step-by-step explanation:

Given the points

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  • (2, -4)

Finding the distance between (-1, 1) and (2, -4) using the formula

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substitute (x₁, y₁) =  (-1, 1)   and  (x₂, y₂) = (2, -4)

   =\sqrt{\left(2-\left(-1\right)\right)^2+\left(-4-1\right)^2}

   =\sqrt{\left(2+1\right)^2+\left(-4-1\right)^2}

   =\sqrt{3^2+5^2}

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