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2 years ago

In your own words, explain what’s happening here. I need help please!! H2+O2+H2O

Chemistry

1 answer:

Yanka [14]2 years ago

4 0

Answer:

Nothing is happening.

Explanation:

As written, nothing is going on. H2+O2+H2O represents a mixture of H2, O2, and H2O. We aren't even given the states, so they may all be gases, liquids/solids, or dissolved gases in a liquid (water).

If we had H2+O2 → H2O, we could say that hydrogen and oxygen are combining to form H2O, water. We should note, however, that the chemical equation is not balanced. There are two oxygen atoms on the reactant side, but only one on the product side. A balanced equation would read:

2H2 + O2 → 2H2O

It would be nice to indicate the physical states, such as:

2H2(g) + O2(g) → 2H2O(l)

Two gases, oxygen and hydrogen, combine to form liquid water.

Also missing from this equation is the energy that may be consumed, or released in this reaction. It would be nice to know, for example, that this reaction releases a lot of energy. Otherwise, we might wind up in the local headlines.

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You carefully weigh 5.724 g of potato flour into a Kjeldahl flask and add an appropriate reagent to digest the flour. You then c

Llana [10]

Hey there!:

In Kjeldahl's method estimation of amount of nitrogen in a sample, the sample is first digested by using sulphuric acid , which converts the nitrogen in the sample to ammonium sulphate.

The ammonium ions in the digested product are converted to ammonia gas by adding excess of base like NaOH. The ammonia gas thus produced is collected by condensation.

The amount of ammonia produced is estimated by titration with standard solution of acid. We are using 0.1 N HCl in this case.

Volume of 0.1 N HCl used = 11.95 mL

Volume of of 0.1 N HCl used in blank titration =0.1 mL

Therefore,actual volume us of 0.1 N HCl

used by analyte( ammonia solution) = 11.95 mL - 0.1 mL

= 11.85 mL

0.1 N HCl = 0.1 M HCl , as HCl is a monobasic acid and therefore its molar mass will be equal to its equivalent mass.

Therefore, concentration of HCl solution used = 0.1 M = 0.1 mol L-1

Volume of HCl solution used =11.85 mL =0.01185 L

Nº.of moles of HCl used = 0.1 mol L-1 * 0.01185 L

= 0.001185 moles

The equation for reaction between NH3 (aq) and HCl during titration is :

NH3 (aq) + HCl (aq) <= > NH4Cl

From the above equation, we see that each mole of HCl reacts completely with 1 mole of NH3 during titration.

Therefore, no. of moles of NH3 that would have been neutralized by 0.001185 moles of HCl = 0.001185 moles

From the formula of NH3 , 1 mole of NH3 contains 1 mole of N atoms.

Therefore, nº of moles of :

N - atoms present = 0.001185 moles

Moar mass of N= 14 g/mol

Mass of 0.001185 moles of N =0.001185 moles * 14 g/ mol

= 0.01659 g

% of N in protein is given as 16%.

16%.of mass of protein = mass of nitrogen in protein sample = 0.01659 g

(16/100) *mass of protein = 0.01659 g

mass of protein = 0.1036875 g

% of protein in potato flour = [mass of protein in potato flour / mass of potato flour] * 100%

( 0.1036875 g / 5.724 ) * 100%

= 1.812 %

Hope this helps!

8 0

3 years ago

A concentration cell consists of two Zn/Zn2+ half-cells. The concentration of Zn2+ in one of the half-cells is 2.0 M and the con

inna [77]

Answer: The EMF of the cell is coming when the cell having diluted concentration is getting oxidized.

Explanation:

We are given a cell which contains two $Zn/Zn^{2+}$ half cells. This means that the standard electrode potential of the cell will be 0.

For a reaction to be spontaneous, the EMF of the cell must be positive. If the EMF of the cell is negative, the reaction will be non-spontaneous and will not take place.

For a reaction to be spontaneous, the diluted cell must get oxidized.

The half reaction for the given cell follows:

Oxidation half reaction: $Zn\rightarrow Zn^{2+}(1.0\times 10^{-3}M)+2e^-$

Reduction half reaction: $Zn^{2+}(2.0M)+2e^-\rightarrow Zn$

Net reaction: $Zn^{2+}(2.0M)\rightarrow Zn^{2+}(1.0\times 10^{-3}M)$

To calculate the EMF of the cell, we use Nernst equation:

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}_\text{{(diluted)}}]}{[Zn^{2+}_{\text{(concentrated)}}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

$[Zn^{2+}_{\text{(diluted)}}]$ = $1.0\times 10^{-3}M$

$[Zn^{2+}_{\text{(concentrated)}}]$ = 2.0 M

Putting values in above equation, we get:

$E_{cell}=0-\frac{0.0592}{2}\log \frac{1.0\times 10^{-3}M}{2.0M}$

$E_{cell}=0.097V$

Hence, the EMF of the cell is coming when the cell having diluted concentration is getting oxidized.

6 0

3 years ago

A 2.98 gram rectangular object has measurements of 21.1 mm, 14.2 mm, and 12.1 mm. What is the object’s density in units of g/mL?

zvonat [6]

Answer:

density = 0.822 g/mL

Explanation:

We calculate the density knowing the flowing formula:

density = mass / volume

mass = 2.98 grams

volume = 21.1 × 14.2 × 12.1 = 3625 mm³ = 3.625 cm³ = 3.625 mL

density = 2.98 / 3.625 = 0.822 g/mL

3 0

4 years ago

A 6.0 mol sample of C3H8(g) and a 20. mol sample of Cl2(g) are placed in a previously evacuated vessel, where they react accordi

gladu [14]

2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed

3 0

4 years ago

Read 2 more answers

Which of the following is true for a system at equilibrium?

Ivan

Answer:

option 1

Explanation:

you can never have all your reactants used up coz it is not possible eg in space u only loose SOme of gravity

8 0

2 years ago