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malfutka [58]
2 years ago
10

The first step in simplifying a rational expression is to.

Mathematics
1 answer:
tekilochka [14]2 years ago
4 0

Answer: To determine the domain the set of all possible inputs of a function which allow the function to work.

Step-by-step explanation:

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HELLPPPPPP -9(x +3) =27<br> -9x + (?) =27 WILL GET BRAINLYIST
Softa [21]

Answer:

-27

Step-by-step explanation:

 Given expression:

                        -9(x + 3)  = 27

               

   Now use the open the bracket;

                       -9x - 27  = 27

           Given  -9x + (?)  = 27

   

Comparing the two equations shows that the question mark corresponds to the value -27;

  The solution is -27

3 0
3 years ago
Find the distance between the two points.
andrew11 [14]

Answer:

-7/-24 or 7/24 simplefied

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which of the following equations have infinitely many solutions?
ohaa [14]
The answer is A because it have infinitely many solutions
5 0
3 years ago
Read 2 more answers
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
Kitty [74]

Answer:

It does not appear ​that, as a​ group, the students are reasonably good at estimating one minute.

Step-by-step explanation:

We are given the following data in the question:

75, 88, 51, 73, 49, 31, 69, 74, 72, 59, 72, 81, 99, 101, 73

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1067}{15} = 71.13

Sum of squares of differences = 4739.733

S.D = \sqrt{\frac{4739.733}{14}} = 18.39

Population mean, μ = 60 minutes

Sample mean, \bar{x} = 71.13 minutes

Sample size, n = 15

Alpha, α = 0.10

Sample standard deviation, s = 18.39 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 60\text{ minutes}\\H_A: \mu \neq 60\text{ minutes}

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{71.13 - 60}{\frac{18.39}{\sqrt{15}} } = 2.34

Calculating the p-value from the table, we have,

P-value = 0.034354

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, we conclude that it does not appear ​that, as a​ group, the students are reasonably good at estimating one minute.

7 0
3 years ago
Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been deter
blondinia [14]

Answer:

The system of hypothesis for this case are:

Null hypothesis: \mu =150

Alternative hypothesis: \mu >150

A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.  

Type II error, also known as a "false negative" is the error of not rejecting a null  hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power.  

Solution to the problem

The system of hypothesis for this case are:

Null hypothesis: \mu =150

Alternative hypothesis: \mu >150

A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.

8 0
4 years ago
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