2 years ago

Please solve this question thank you

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

6 0

Answer:

angle ABC = 30°

Step-by-step explanation:

I attached a picture. if any part is not understandable leave a comment.

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bagirrra123 [75]

$\lim_{n \to \ 0 } \frac{7n-8n}{2n} = \lim_{n \to \ 0 } \frac{-n}{2n} 
= \lim_{n \to \ 0 } \frac{-1}{2} = \frac{-1}{2}$

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3 years ago

Which is the equation of a parabola with vertex (0, 0), that opens to the left and

andrezito [222]

Answer:

Step-by-step explanation:

I'm going to guess that the square exponents are on the top y's only? then answer b) looks good

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3 years ago

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A road has a scale of 1:50 000 The length of a road on the map is 8.5cm.Work out the length of the real road in kilometres

uranmaximum [27]

The answer is 2.1 Km. Hope this helps!

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3 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

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3 years ago

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Assoli18 [71]

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3 years ago