If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius, ° was the temperature at noon
<u>Step-by-step explanation:</u>
Here we have , If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius . We need to find what was the temperature at noon . Let's find out:
Let us suppose that initially we have temperature x° , So the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius , i.e.
⇒
Adding 4.4 both sides:
⇒
⇒
⇒ °
Therefore , If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius, ° was the temperature at noon .
In 15 minutes there will be 80 people at the art show.
Answer:
x = -4
Step-by-step explanation:
The axis of symmetry of a quadratic function must be equidistant from both branches of the parabola that the quadratic function describes. therefore, the axis of symmetry must be a vertical line that lies at exactly the middle point between the crossings of the parabola branches on the x axis.
These two crossings are the zeroes of the parabola (given as -12 and 4).
So we notice that the distance between these two points is 16 units: |12-(-4)| = 16. Therefore the axis of symmetry should be located at half distance from these two points, that is: at 8 units from each.
This makes the axis' position 8 units to the right of "-12", which gives x = -4.
Then the equation of the axis of symmetry for this quadratic function must be the vertical line defined by:
x = -4
Answer:
$165.62
Step-by-step explanation:
Multiply principle(910) by rate (0.052) and time (3.5)= interest(165.62)