What is the factored form of n3+512 (pleas help fast)
2 answers:
Answer:
Since both terms are perfect cubes, factor using the sum of cubes formula,
a³+b³=(a+b)(a²-ab+b²) where
a=n and b=8
(n+8)(n²-8n+64)
<em><u>Answer </u></em>
<em><u>(</u></em><em><u>n+</u></em><em><u>8</u></em><em><u>)</u></em><em><u>(</u></em><em><u>n²</u></em><em><u>-</u></em><em><u>8</u></em><em><u>n</u></em><em><u>+</u></em><em><u>6</u></em><em><u>4</u></em><em><u>)</u></em>
<em><u>hi </u></em>
<em><u>have </u></em><em><u>a </u></em><em><u>good </u></em><em><u>day</u></em>
<em><u>thank </u></em><em><u>me </u></em><em><u>later</u></em>
<em><u>Carryonlearing </u></em>
Answer:
Step-by-step explanation:
The only one that has a chance of being correct is D. That's because the first term is correct and you have to assume that the second one is as well.
cubrt(512) = 8
The first term is (n + 8)
The second term is (n^2 - 8*n + 8^2) = n^2 - 8n + 64
All the other answers have the wrong first term
A: it should be n + 8 not n - 8
B and C are both wrong because the cube root of 512 is 8 not 4.
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