All categories

2 years ago

Need help ASAP!!!

Mathematics

1 answer:

kykrilka [37]2 years ago

5 0

Answer: 60kg

Step-by-step explanation:

60 kg

You might be interested in

H. E. L. P. ???!!!!!!

vladimir1956 [14]

Answer:

Step-by-step explanation:

sin x= CB/CA =4/8

......

4 0

3 years ago

Find an equation that models the path of a satellite if its path is a hyperbola, a = 55,000 km, and c= 81,000 km. Assume the cen

elena-14-01-66 [18.8K]

Answer:

$\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1$

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

$\frac{x^2}{a^2} - \frac{y^2}{b^2} =1$

Given a= 55000 and c= 81000

c^2 = a^2 + b^2

81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

$\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1$

7 0

3 years ago

Given the following table, what is the quadratic equation?

rusak2 [61]

Answer:

144322221111155554444444333222222

7 0

3 years ago

A person is standing 50 ft from a statue. The person looks up at an angle of elevation of 8 degrees when staring at the top of t

borishaifa [10]

The height of the statue is 19.5 feet.

Why?

We can solve the problem using trigonometric formulas. In this case, we are going to use the trigonometric formula of the tangent.

We know that the person is standing 50ft from the statue, so, it will be the base of the two triangles formed by both angles (elevation and depression)

Using the trignometric formula, we have:

First triangle:

$tg(\alpha )=\frac{h_{1}}{base} \\\\tg(8\°)=\frac{h_{1}}{50ft}\\\\0.14*50ft=h_1\\\\h_1=7ft$

Second triangle:

$tg(\alpha )=\frac{h_{2}}{base} \\\\tg(14\°)=\frac{h_{1}}{50ft}\\\\0.25*50ft=h_1\\\\h_1=12.5ft$

Now, the total height of the statue will be:

$TotalHeight=h_1+h_2=7ft+12.5ft\\\\TotalHeight=19.5ft$

Have a nice day!

8 0

3 years ago

The graph of f (0) = -4 cos 0 is shown below. The range of this function is

Anika [276]

Answer:

-4 ≤ f ( $\theta$ ) ≤ 4

Step-by-step explanation:

The range of a function is the allowed y-values of the function.

We can simply look at the periodic function below and see that the y-value ranges from a negative 4 to a positive 4. It oscillates betwen -4 and 4. That is the range.

We can say -4 ≤ f ( $\theta$ ) ≤ 4

Last answer choice is right.

*** <u>NOTE:</u> it is a type, not "0", rather " $\theta$ "

5 0

3 years ago