Answer: a - 4
b - 1
c - 2
d - 3
e - 5
Step-by-step explanation:
1. 6, 12, 18
2. 8,16,24
3. 12, 24, 36
4. 15, 30, 45, 60
4. 30, 60, 90
Answer:

Step-by-step explanation:
6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:
6•5•4•3 = 360
If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.
So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:
1•1•4•3 = 12
The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

Answer:
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I would go with C. like the other person