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babunello [35]
2 years ago
13

I’ll rate u 5 stars quick response really fast what is the range image

Mathematics
1 answer:
lions [1.4K]2 years ago
4 0
Range is all y-values. This would be all real numbers or (-oo,oo)
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5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
-X + 2y = 10<br> -3x+ 6y = 11
Tanzania [10]

Answer:

1. y = 1 /2X +5

Step-by-step explanation:

2. m=1/2

7 0
2 years ago
f(x) = x^2 – 3x +18 What is the value of the discriminant of f? How many distinct real number zeros does ſ have?​
seraphim [82]

Answer:

0+=x^2-3x+18

Step-by-step explanation:

I'm smort- but if its wrong I apologize

4 0
2 years ago
If the first step in the solution of the equation -9+x=5x-7 is "subtract x", then what should the next step be
kicyunya [14]
The next step would be 10n=5x-7+9-x
sincerely- brock<span />
8 0
3 years ago
Mike drove 100 miles in a rental car and was charged $58.00. Jane rented the same car after Mike had rented it and was charged $
timama [110]

Answer:

y= 48 + 0.1x

x= miles driven

Step-by-step explanation:

<u>We need to calculate the fixed and variable cost (per mile) of renting a car. To do that, we will use the high-low method:</u>

Variable cost per unit= (Highest activity cost - Lowest activity cost)/ (Highest activity units - Lowest activity units)

Variable cost per unit= (65 - 58) / (170 - 100)

Variable cost per unit= $0.1 per mile

Fixed costs= Highest activity cost - (Variable cost per unit * HAU)

Fixed costs= 65 - (0.1*170)

Fixed costs= $48

Fixed costs= LAC - (Variable cost per unit* LAU)

Fixed costs= 58 - (0.1*100)

Fixed costs= $48

y= 48 + 0.1x

x= miles driven

7 0
3 years ago
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