Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF
In a cuboid, FA = BG = CH = DE = 9.3
The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
Scale factor is defined as a number which multiplies or scales some quantity.
The shape of the figure remains same, the image becomes larger or smaller.
If the scale factor is greater than one, then the image is enlarged.
If the scale factor is less than 1 but greater that 0, then the image becomes smaller.
In the above image, AD = 2 units.
It's corresponding side PS = 3 units
Similarly AB = 1 unit and PQ = 1.5 units
Hence , 1 * 1.5 = 1.5
2*1.5 = 3
Hence, the scale factor of the given image is 1.5 ... Answer
64/3274=0.019547954
Hope this helps.
S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n
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