Ask question

Ask question

All categories

3 years ago

7

Bought five lip balms. Each lip balm costs the same amount. She spent a

1 answer:

Juli2301 [7.4K]3 years ago

6 0

The equation for your question would be 7.25= 5c :)

You might be interested in

Match the equation with its graph. -2/3x - -1/4y=1/3

Volgvan

If the equation is -(2/3) x - (1/4) y = 1/3, it is a straight line, so you can use some special points to identify the graph.

It is easier is you solve the equation for y:

(1/4)y = - 1/3 - (2/3) x

y = (-4/3) - (8/3)x

That is the slope -y-intercept form of the equation.

That means that the slope is -8/3, and the y-intercept is -4/3.

Use this points to identify the graph:

x = 0 => y = - 4/3 ---> (0, - 4/3)

y = 0 => x = - 1/2 -----> (-1/2, 0)

Now you can punt those two points on the graph and draw the line that joins them.

With this procedure you can find the graph of any straight line.

4 0

3 years ago

Can you answer these two questions please 10 points

ioda

I don’t understand either

6 0

3 years ago

11xto the 7th power ×6x to the 5th power

solong [7]

The first one is 19,487,171 and the second is 7,776

6 0

3 years ago

Given that the length a < b, what is the order of the angles ∠ABC, ∠ACB, and ∠CAB from least to greatest?

elena-s [515]

The answer is C because an angle is determined by the letter in the middle. It is given that a is smaller than b and c=90

8 0

3 years ago

Read 2 more answers

A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha

Mars2501 [29]

Here we know that the initial velocity of the car is given by:

$V_i=(3.0\hat x+1.0\hat y)m/s$

And the final velocity of the car is given by:

$V_f=(6.0\hat x-3.0\hat y)m/s$

It took 3 seconds to attain the final velocity, so we have $t=3 s$

Therefore, the acceleration can be obtained by:

$V_f-V_i=a\times t$

$a=\frac{V_f-V_i}{t}$

Plugging the values of the initial, final velocity and the time, we get:

$a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}$

So the acceleration of the car is given by:

$a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y$

Now we need to find the direction of the average acceleration of the car:

$\theta=tan^{-1} \frac{y}{x}$

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

$\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ$

Therefore, the direction of the average acceleration of the car is $-53.13^\circ$ .

8 0

4 years ago