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3 years ago

In what chapter did sal meet Margreat

SAT

1 answer:

drek231 [11]3 years ago

8 0

Answer: Chapter 3: Bravery.

Explanation: Sal begins the story with her first moments in Lewiston. She overhears Margaret pleading with her father to tell Sal how they met, but Sal rudely refuses to hear the story. Sal marches glumly through their new house, situated only a few blocks from Margaret's, complaining about its size.

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How many photons are contained in a burst of green light (525 nm) that contains 125 kj of energy?

Tresset [83]

I think that the answer is =4.99e23 photons hope this works!

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3 years ago

A man went outside in the pouring rain with no protection, but not a single hair on his head got wet. How come?

charle [14.2K]

Answer:

He’s magic

Explanation:

Because he is

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3 years ago

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Two congruent squares are shown in figures 1 and 2 below.

Natalija [7]

The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2. The area of the unshaded square in Figure 1 can be represented by . The combined area of the two unshaded squares in Figure 2 can be represented by . The areas of the squares in Figure 1 and Figure 2 show that .
Given :
Figure 1 and figure 2 are given.
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2.
The area of the unshaded square in Figure 1 can be represented by .
The combined area of the two unshaded squares in Figure 2 can be represented by .
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4 0

2 years ago

Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM

Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

#include <cmath>

#include "pppm_tip4p.h"

#include "atom.h"

#include "domain.h"

#include "force.h"

#include "memory.h"

#include "error.h"

#include "math_const.h"

using namespace LAMMPS_NS;

using namespace MathConst;

#define OFFSET 16384

#ifdef FFT_SINGLE

#define ZEROF 0.0f

#define ONEF 1.0f

#else

#define ZEROF 0.0

#define ONEF 1.0

#endif

void PPPMTIP4P::init()

{

// TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms

if (force->newton == 0)

error->all(FLERR,"Kspace style pppm/tip4p requires newton on");

PPPM::init();

}

void PPPMTIP4P::particle_map()

{

int nx,ny,nz,iH1,iH2;

double *xi,xM[3];

int *type = atom->type;

double **x = atom->x;

int nlocal = atom->nlocal;

if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))

error->one(FLERR,"Non-numeric box dimensions - simulation unstable");

int flag = 0;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;

ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;

nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;

part2grid[i][0] = nx;

part2grid[i][1] = ny;

part2grid[i][2] = nz;

if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||

ny+nlower < nylo_out || ny+nupper > nyhi_out ||

nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;

}

int flag_all;

MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);

if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");

}

void PPPMTIP4P::make_rho()

{

int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;

FFT_SCALAR dx,dy,dz,x0,y0,z0;

double *xi,xM[3];

FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];

for (i = 0; i < ngrid; i++) vec[i] = ZEROF;

int *type = atom->type;

double *q = atom->q;

double **x = atom->x;

int nlocal = atom->nlocal;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = part2grid[i][0];

ny = part2grid[i][1];

nz = part2grid[i][2];

dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;

dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;

dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;

compute_rho1d(dx,dy,dz);

z0 = delvolinv * q[i];

for (n = nlower; n <= nupper; n++) {

mz = n+nz;

y0 = z0*rho1d[2][n];

for (m = nlower; m <= nupper; m++) {

my = m+ny;

x0 = y0*rho1d[1][m];

for (l = nlower; l <= nupper; l++) {

mx = l+nx;

density_brick[mz][my][mx] += x0*rho1d[0][l];

}

}

See more about C++ at brainly.com/question/19705654

#SPJ1

6 0

2 years ago

Square root of root 25

Mamont248 [21]

Explanation:

its 5

the answer is 5

hope it helped

3 0

3 years ago

Read 2 more answers