The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
Read more about congruent triangles at:
brainly.com/question/12413243
#SPJ1
<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
A: 6/8, 9/12, 12/16
b: 6/14, 9/21, 12/28
c: 6/9, 2/3, 4/6
d: 1/4, 2/8, 2/12
In order to find equivalent fractions for a fraction is multiply or divide the numerator and denominator by the same number.
For example, 3/4=6/8 because 3x2=6 and 4x2=8, 6/8.
Hope this helps!
A triangle is the anwser because it is made of many triangles
Answer:
<em>y = - 3x + 4 </em>
Step-by-step explanation:
m = 
y - 
= m( x - 
) Point-slope form
y = mx + b Point-intercept form
(1, 1)
(2, - 2)
m = (- 2 - 1 ) / (2 - 1) = - 3
y - 1 = - 3( x - 1 )
<em>y = - 3x + 4</em>
Answer:
my answer would be c. y=lX+7l
