All categories

2 years ago

What is the slope of the line in the graph? answer fast help plzzz

Mathematics

1 answer:

ziro4ka [17]2 years ago

4 0

The slope can be found by using the slope formula.

Slope = y2 - y1 / x2 - x1

First, we need two points on the line.

(-1, 0) and (0, 1)

x1 = -1 and y1 = 0

x2 = 0 and y2 = 1

Let's plug these values into our slope formula.

(1 - 0) / (0 - (-1)) = 1 / 1 = 1

The slope is 1

You might be interested in

When multiplying 2.94 by 3.045, the answer should have how many significant digits after the decimal point?

Ratling [72]

Answer:

4 beacause when we multiply it will be 8.9523

6 0

1 year ago

A roulette wheel has 38 slots. a gambler will play roulette 50 times, betting a dollar on four numbers each time. if one of thes

Keith_Richards [23]

For 1 play, the chance of gaining $8 is 4/38, while the chance of losing the $1 is 34/38. Therefore, the expected value is ($8)(4/38) + ($-1)(34/38) = $(-1/19). Over 50 plays, which are mutually independent of each other, we multiply the number of plays by the expected value to get $(-50/19) = $-2.63.
<span />

7 0

2 years ago

I need help combining functions!

postnew [5]

$\bf \begin{cases}
f(x)=\cfrac{2}{x}\\\\
g(x)=\cfrac{x}{x+2}
\end{cases}\qquad g[\quad f(x)\quad ]=\cfrac{[f(x)]}{[f(x)]+2}$

$\bf (g\circ f)(x)\iff g[\quad f(x)\quad ]=\cfrac{\boxed{\frac{2}{x}}}{\boxed{\frac{2}{x}}+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{\frac{2}{x}}{\frac{2x+2}{x}}\implies g[\quad f(x)\quad ]=\cfrac{2}{x}\cdot \cfrac{x}{2x+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{2x}{2x^2+2x}\implies g[\quad f(x)\quad ]=\cfrac{2x}{2x(x+1)}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{1}{x+1}$

5 0

2 years ago

Find the exact length of the third side

VMariaS [17]

Answer:

2 root 15

Step-by-step explanation:

2 squared + x squared= 8 squared

4+ x squared= 64

xsquared =60

square root of sixty = 2 root 15

3 0

2 years ago

Given x^2 + y^2 = 36 and xy = -10 find x + y.

9966 [12]

This looks fun

ok so
we will use subsitution
xy=-10
divide both sides by x or y (I will choose y)
x=-10/y

sub -10/y fo x

(-10/y)^2+y^2=36
100/(y^2)+y^2=36
times both sides by y^2
100+y^4=36y^2
minus 36y^2 from both sides
y^4-36y^2+100=0
(y^2)^2-36(y^2)+100=0
quadratic formula
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
x= $\frac{-(-36)+/- \sqrt{(-36)^2-4(1)(100)} }{2(1)}$
x= $18+/- 4\sqrt{14}$

sub
y=-10/x
y= $\frac{-10}{18+/- 4\sqrt{14}}$

so x+y= $18+/- 4\sqrt{14}$ + $\frac{-10}{18+/- 4\sqrt{14}}$
multiply first number by $\frac{18+/- 4\sqrt{14}}{18+/- 4\sqrt{14}}$ and add them

x+y= $\frac{(18+/- 4\sqrt{14})(18+/- 4\sqrt{14})-10}{18+/- 4\sqrt{14}}$
or
x+y= $\frac{81+22 \sqrt{14} }{5}$ or $\frac{81-22 \sqrt{14} }{5}$

8 0

2 years ago