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3 years ago

What is the slope of the line in the graph? answer fast help plzzz

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

The slope can be found by using the slope formula.

Slope = y2 - y1 / x2 - x1

First, we need two points on the line.

(-1, 0) and (0, 1)

x1 = -1 and y1 = 0

x2 = 0 and y2 = 1

Let's plug these values into our slope formula.

(1 - 0) / (0 - (-1)) = 1 / 1 = 1

The slope is 1

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For how many positive integers n is it possible to have a triangle with side lengths five, 12, and n

Andre45 [30]

Step-by-step explanation:

you know, a single side cannot be longer than the other 2 sides combined.

otherwise, the triangle cannot "close".

so, it starts with 12 cannot be longer than 5 + n.

therefore, n must be at least 7.

and n cannot be longer than 5+12 = 17

7 and 17 I would normally rule out a well, because in these cases the triangle would just be a flat line, when the 3rd side is as long as the other 2 combined.

so, in reality for a real, visible triangle, the range of valid values is 8 .. 16.

that is 9 positive integer values.

8 0

3 years ago

Please help

Katarina [22]

Answer:

Step-by-step explanation:

$\left \{ {{2x+3y=15} \atop {x-3y=3}} \right.$

4 0

2 years ago

Use the Distributive Property to expand 9(3 + x).

tankabanditka [31]

Distribute the 9 to each term in the parentheses with multiplication.

9(3 + x) = 27 + x

But this is usually written as x + 27

4 0

3 years ago

Read 2 more answers

Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)

IrinaK [193]

Answer:

Equation of the circle (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

Step(i):-

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

Centre = $(\frac{-2+8}{2} ,\frac{1+9}{2} )$

Centre (h, k) = (3 , 5)

Step(ii):-

The distance of two end points

PQ = $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$

$PQ= \sqrt{(8+2 )^{2} +(8 )^{2} }$

PQ = √164 = 12.8

Diameter d = 2r

radius r = d/2

Radius r = 6.4

Final answer:-

Equation of the circle

(x-h)²+(y-k)² = r²

(x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x +y² -10y = 40.96-34

x² -6x +y² -10y -7= 0

4 0

4 years ago

Subtract 7 pounds 3 ounces from 10 pounds

butalik [34]

(10 pounds) - (7 pounds 3 ounces) =
2.8125 pounds

7 0

3 years ago