Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:

In which a is the probability that a customer saw the advertisement on the internet but not on television and
is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:

12% saw it on both the internet and on television.
This means that 
20% saw it on television
This means that 
37% of customers saw the advertisement on the internet
This means that 
What is the probability that a randomly selected customer saw the advertisement on the internet or on television

45% probability that a randomly selected customer saw the advertisement on the internet or on television
-the shower block as an area of 144m^2-the length of the shower block is 24m
Area= length x width
Plug in the values you know.
144= length*24
Divide both sides by 24.
length=6
The width of the shower block is 6m.
I hope this helps!
Answer:
y=2/3x+1/6
Step-by-step explanation:
Answer:
.5, sqrt 14, 4
Step-by-step explanation:
.5, 3.7416, 4
You would multiply the two terms which are -6y^2 and -13x^2*y^5.
Multiplying -6 by -13 yields 78, which will be the new coefficient.
Since there is only the x^2 from the second term, that remains the same. However, there are two y values that we can multiply together: y^2 and y^5. y^2 * y^5 = y^(2 + 5) = y^7.
Therefore, your answer is 78x^2*y^7.