Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic

p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Answer:
the correct answer is -3.125
Step-by-step explanation:
Answer:
24%
Step-by-step explanation:
25 - 19 = 6
25 = 100%
2.5 = 10%
1.25 = 5%
0.25 = 1%
5 = 20%
1 = 4%
6 = 24%
Hope this helps :)
<u>exact form:</u>
w= 74/45
<u>decimal form:</u>
w= 1.64
<u>mixed number:</u>
w= 1 29/45
brainliest would be appreciated :)