Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
( 2x - 3 ) / 5
Step-by-step explanation:
2x - 6 = 5y - 3
2x - 6 + 3 = 5y
2x - 3 = 5y
y = ( 2x - 3 ) / 5
If you do x- number of water cups 1 over 8 will equal 32 over x ,x=256 so 256
if this makes any sense if not ill try better to explain
The answer should be D since after 5 am to 7 am only two hours have passed so x=2, and then you plug in the x as 2 and solve it. You might get not around answer like 39.785 but when you round it, it would be 40.
