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Mars2501 [29]
3 years ago
7

HELP

Mathematics
1 answer:
Bumek [7]3 years ago
7 0

Answer:B.x = 2

because 1 < x < 13 => x ≠ {0;14}

Step-by-step explanation:

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Consider the equation 5 + x = n
Inga [223]
All of the answers will be less than five. for example if x=-3 n=2 which is less than 5
3 0
2 years ago
The number of girls at middle school Cyber summer camp was six more than twice the number of boys. The total of 156 middle schoo
Sloan [31]
Girls: 81
boys: 75

4x +6 = 156
4x = 150
x = 37.5
2x = 75

girls: 75 + 6
boys: x
7 0
3 years ago
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
A circular playground force daycare center is to be covered with square tiles that are 9 inches on each side. The circle has a d
Luda [366]

You would need 9 boxes of tiles to cover it.


I hope this helps! :)

7 0
3 years ago
Read 2 more answers
A jacket that is regularly sold for $49.95 is on sale for 25% off. What is the sale price of the jacket?
Gnoma [55]

First, find 25% of 49.95. Turn 25% into a decimal by dividing by 100.

25% ⇒ 0.25

Now, multiply 0.25 by 49.95.

0.25 × 49.95 = 12.46

25% of 49.95 is 12.46, so subtract 12.46 from 49.95.

49.95 - 12.46 = 37.49

<h2>Answer:</h2>

<u>The discounted price of the jacket is </u><u>$37.49</u><u>.</u>

Now find 8% of 37.49.

8% ⇒ 0.08

Multiply 0.08 by 37.49.

0.08 × 37.49 = 2.99

<h2>Answer:</h2>

<u>The tax is </u><u>$2.99</u><u>.</u>

To find the full price, add 37.49 and 2.99 together.

37.49 + 2.99 = 40.48

<h2>Answer:</h2>

<u>The final cost is </u><u>$40.48</u><u>.</u>

4 0
3 years ago
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