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BartSMP [9]
3 years ago
7

Jillian has $50.45 to spend on hamburgers and drinks. Hamburgers are $2.25 each. What is the LARGEST number she can buy and stil

l have at least $10 left over for drinks?
A) 13
B) 14
C) 15
D) 17
Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0
2.25 x 17 = 38.25. 50.45 - 38.25 = 12.20. If Jillian buys 17 hamburgers, she will still have $12.20 left over which is more than $10 so your answer is D) 17.

Hope this helps,
♥Nikki♥
Alexus [3.1K]3 years ago
5 0
Your answer is C



Hope this helps :D
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You roll a six sided die. What is the probability of rolling a 1 or a number greater than 4.
Romashka [77]

A. 1/2

This is because there are 6 possible outcomes. 1, 2, 3, 4, 5, and 6.

The probability of rolling 1, 5, and 6 is 3 out of 6 (3/6)

3/6 reduced is 1/2.

3 0
3 years ago
The first five terms of a pattern are shown.
Andrej [43]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

\frac{3}{10} ÷ \frac{3}{100} = 3 ÷ \frac{3}{10} = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = \frac{3}{100} and r = 10 , thus

a_{n} = \frac{3}{100} (10)^{n-1}

    = \frac{3}{10^{2} } × 10^{n-1}

    = 3 × 10^{-2} × 10^{n-1}

    = 3 × 10^{n-3}

Thus

a_{n} = 3(10)^{n-3} → C

6 0
3 years ago
If May was going to the prom and asked out 98 boys to go to the prom with her and 50% of the boys touched held her hand, made ey
tangare [24]

Answer:

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7 0
3 years ago
Read 2 more answers
Quadratic Equation
Natasha_Volkova [10]

Step-by-step explanation:

The sum of ages of two friends is 13 years.

The product of their ages is 42.

<em>Let the age of 1st friend and 2nd friend is x, y respectively.</em>

<em>1 st condition= The sum of ages of two friends is 13 y</em><em>r</em><em>s. </em>

i.e x+y = 13........ (I)

<em>2nd condition= The product of their ages is 42.</em>

i.e X*y = 42........(ii)

From equation (I)

X+y = 13

or, X = 13-y........ (iii)

<em>Putting the equation (iii) in equation (ii).</em>

X*y= 42

(13-y) * y = 42

13y - y^2 = 42

{y}^{2}  - 13y + 42 = 0

{y}^{2}   - (7 + 6)y + 42= 0

{y}^{2}  - 7y - 6y + 42 = 0

y(y - 7) - 6(y - 7) = 0

(y - 6) (y - 7) = 0

Either; y-6 = 0

y = 6

Or;

y-7=0

y = 7

<em>Keeping the value of y as "7" in equation (ii)</em>

x*y = 42

7x = 42

X = 42/7

Therefore, the value of X is 6.

Therefore, either 1st friend is 6 years and 2nd is 7 years.

<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Find the limit as t approaches 8 for the function f(t)=7(t-1)(t-1)
Ratling [72]

Answer:

7³

Step-by-step explanation:

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5 0
3 years ago
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