Answer:
0.6 is the probability of success of a single trial of the experiment
Complete Problem Statement:
In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by 
What is the probability of success of a single trial of this experiment?
Options:
Step-by-step explanation:
So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:
=
now,

so,
by comparing with
, we get:
μ=np=27
=3.29
put np=27
we get:
=3.29
take square on both sides:
10.8241=27-27p
27p=27-10.8241
p=0.6
Which is the probability of success of a single trial of the experiment
Answer:
The least common denominator is 21
Step-by-step explanation:
3 & 7 equal 21 which is the least common factor that it equals
remember that
![x^{\frac{a}{b}}=\sqrt[b]{x^a}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
also 
and 
so

first one, that one is clearly not equal since 0.25≠4
2nd one, 0.25=1/4, so
, which matches
3rd one,
, which matches
4th one
which matches
answer is 