Answer:
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
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Step-by-step explanation:
The SI unit of work is Joule.
Further more explanation:
▪️
⇒Work done by a force acting on a body is defined as the product of force and displacement of the body in the direction of the force.
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⇒The system of units which is agreed by the international convention of scientists held in France in 1960 is called SI unit.
▪️
⇒One joule is the amount of work done when one Newton force displaces a body through one metre in its own direction.
Hope I helped!
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Answer:
More than 10% of Gillway students earned honors.
Step-by-step explanation:
<u>Step 1: Find the number of students who earned honors</u>
43 + 17 = 60
<u>Step 2: Find the total number of students</u>
381 + 108 = 489
<u>Step 3: Find the percentage of students who earned honors</u>
Students who earned honors/Total students x 100
60/489 x 100
12.27%
<u>Step 4: Find the correct answer</u>
Just under 11% of Gillway students earned honors.
<em>This is incorrect since the percentage is more than 11%.</em>
Just over 11% of Gillway students earned honors.
<em>This is incorrect as just over 11% would mean somewhere between 11 and 12% whereas the actual percentage is just over 12%.</em>
More than 10% of Gillway students earned honors.
<u><em>This is correct as compared to all other statements since 12.27% is more than 10%.</em></u>
Almost 11% of Gillway students earned honors.
<em>This is incorrect since almost 11% means less than 11% whereas the actual percentage is more than 11%.</em>
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Answer:
Step-by-step explanation:
L and W are the length and width of the garden, respectively.
perimeter = 2L+2W = 38 ft
L+W = 19
the length is 5 ft longer than the width
L = W+5
substitution
(W+5)+W = 19
2W+5 = 19
W = 7