Another math question ... I really dont understand this one so can somebody help?

Mathematics

2 answers:

Irina18 [472]3 years ago

6 0

Answer:

7 1/3 ft

Step-by-step explanation:

22 divided by 3 equals 7 1/3

densk [106]3 years ago

4 0

The answer to your question would be eleven if I am correct

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The second on a watch is 14mm long. What area does it sweep through in 30 seconds

skad [1K]

Exact Area = 98pi

Approximate Area = 307.8760800518 (use calculator stored version of pi)

Approximate Area = 307.72 (using pi = 3.14)

Units are in square millimeters

======================================================

Explanation:

In 60 seconds, the hand sweeps out a full circle of radius 14. The area of this circle is

A = pi*r^2 = pi*14^2 = 196pi

Half of this is what the hand sweeps out in 30 seconds, so A/2 = (196pi)/2 = 98pi is the exact area it sweeps out. Your calculator would then show 98pi = 307.8760800518 approximately

If instead you use pi = 3.14, then the approximate area is 98*3.14 = 307.72

3 0

3 years ago

40 points and brainliest

lidiya [134]

Answer:

Here you go

10:

11:

12:

13:

3 0

2 years ago

use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11

Evgen [1.6K]

So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus $\bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1$

so... what' the point h,k for the center? well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"? well, "b" comes from the conjugate axis, or the other runnning over the x-axis hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is $\bf c=\sqrt{a^2+b^2}$

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus $\bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b$

that'd be "b"

bearing in mind that $\bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}$