Which equation represents the line that is perpendicular to and passes through (-12,6)?.

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

7 0

The equation that represents the line that is perpendicular is

3y + 5x = -42

The standard equation of a line in point-slope form is expressed as:

$y-y_1=m(x-x_1)$

m is the slope of the lne

(x1, y1) is any point on the line.

Given the equation y = 3/2x + 1, the slope of the line is 3/5

The s<u>lope of the line perpendicular</u> is -5/3

Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

$y-6=-5/3(x-(-12))\\3(y-6)=-5(x+12)\\3y-18=-5x-60\\3y = -5x - 60 + 18\\3y + 5x = -42\\$

Hence the equation that represents the line that is perpendicular is

3y + 5x = -42

Learn more on equation of a line here:brainly.com/question/19417700

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