Answer:
Since a/2⁽ⁿ ⁺ ¹⁾b < a/2ⁿb, we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.
Step-by-step explanation:
Let a/b be the rational number in its simplest form. If we divide a/b by 2, we get another rational number a/2b. a/2b < a/b. If we divide a/2b we have a/2b ÷ 2 = a/4b = a/2²b. So, for a given rational number a/b divided by 2, n times, we have our new number c = a/2ⁿb where n ≥ 1
Since
= a/(2^∞)b = a/b × 1/∞ = a/b × 0 = 0, the sequence converges.
Now for each successive division by 2, a/2⁽ⁿ ⁺ ¹⁾b < a/2ⁿb and
a/2⁽ⁿ ⁺ ¹⁾b/a/2ⁿb = 1/2, so the next number is always half the previous number.
So, we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.
Step-by-step explanation:
-1,6 is -1 left 6 up
1,-6 is 1 right -6 down
6,-1 is 6 right -1 down
To find angle c, the fourmula is 1/2 of the intercepted arc. so, this would be (-3x-6)=(-4x)/2, then bring the 2 over, (-3x-6)2=-4x, multiply the 2, -6x-12=-4x, -2x=12, simplify, x=-6
check by plugging in.
4x+1+57=90
4x+58=90
4x=32
X=8