Option A: The sum for the infinite geometric series does not exist
Explanation:
The given series is 
We need to determine the sum for the infinite geometric series.
<u>Common ratio:</u>
The common difference for the given infinite series is given by
Thus, the common difference is 
<u>Sum of the infinite series:</u>
The sum of the infinite series can be determined using the formula,
where 
Since, the value of r is 3 and the value of r does not lie in the limit
Hence, the sum for the given infinite geometric series does not exist.
Therefore, Option A is the correct answer.
Answer:
He would make $36 for 12 pounds of strawberries
He would make $196 for 49 pounds of blueberries
He would make 3S if he sold S pounds of strawberries
He would make 4B if he sold B pounds of blueberries
Working:
We know that strawberries are $3/pound so $3 x 12pounds = $36
We know that blueberries are $4/pound so $4 x 49pounds = $196
The letters represent the amount of pounds of fruit being bought so the calculation for that is ($ x pounds) so you would write this but without assigning a numerical value to the amount. So if the strawberries are $3/pound and Luke sold ‘s’ pounds then it would be 3S (or 3xS but that is already assumed). The same goes for the blueberries. We know that they are $4/pound so it would be 4B.
Sorry if this doesn’t make any sense but I hope this helped
Answer:
THANK YOU 505
Step-by-step explanation:
We need to solve for x. Let's try problem b:
Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:
Since this is true, your answer would be:
All real numbers
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Let's solve for problem c:
Let's isolate x, so subtract 1 from both sides:
Since x can't have a coefficient, divide both sides by 3:
So, only the value of 14 would make this equation true.
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Let's try problem d:
Let's get our whole numbers on the right side. Add 1 to both sides:
Subtract 4x from the right side on both sides:
Since this is not true, your answer would be:
No solution
The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
