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3 years ago

Alguien me ayuda Gracias

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

1) V

2) V

3) V

4) V

5) V

Step-by-step explanation:

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Answer:table 1 would be y=x-3 and table 2 is y=x-5

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3 years ago

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dem82 [27]

Answer: 1. Angle MHG 2. Angle LHM 3. Angle LHK and KHJ and the measures are 35 each

Step-by-step explanation:

1. The order you put the angle points in isn’t super important, as long as the middle point of the angle stays between the two letters, so angle ABC can be angle CBA as long as the b stays in the middle

2. You can find out the LHM is a right angle by looking at the protractor and counting

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3 years ago

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nevsk [136]

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3 years ago

Initially a pool contains 350 gallons of water. A hose is placed in the pool and the water is turned on. The hose adds 5.2 gallo

frez [133]

Answer: 350 + 5.2x = V

Step-by-step explanation:

350 + 5.2x = V

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3 years ago

Prove that T is one to one if and only if T carries linearly independent subsets of V onto linearly independent subsets of W.

balu736 [363]

Answer with Step-by-step explanation:

Suppose T is one-one

Let S be a linearly independent subset of V

We want to show that T(S) is linearly independent.

Suppose T(S) is linearly dependent.

Then there exist $v_1,v_2,...v_n\in S$ and some not all zero scalars $a_1,a_2,....a_n$ such that

$a_1T(v_1)+a_2T(v_2)+a_3T(v_3)+...+a_nT(v_n)=0$

T is linear therefore,

$T(a_1v_1+a_2v_2+..+a_nv_n)=0$

T is one-one therefore

N(T)=0

$a_v_1+....+a_nv_n=0$

S is linearly independent therefore,

$a_1=a_2=...a_n=0$

It is contradiction.Hence, T(S) is linearly independent.

Conversely, Suppose that T carries linearly independent subset of V onto linearly independent subsets of W.

Assume that T(x)=0 if the set x is linearly independent

Then, by assumption we conclude that {0} is linearly independent but {0} is linearly dependent.

It is contradiction .Hence, the set {x} is linearly dependent which implies that x=0

It means N(T)={0}.Therefore, T is one- one

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3 years ago