In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it. If they still
have a common factor, then divide them by it again. Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.
Do 15 and 40 have any common factors ?
Let's see . . .
The factors of 15 are 1, 3, <em>5</em>, and 15 .
The factors of 40 are 1, 2, 4,<em> 5</em>, 8, 10, 20, and 40 .
Ah hah ! Do you see that ' <em>5</em> ' on both lists ? That's a common factor.
So 15/40 is NOT in lowest terms.
Divide the numerator and denominator both by 5 :
15 / 40 =<em> 3 / 8</em>
3 and 8 don't have any common factor except ' 1 '.
So 3/8 is the same number as 15/40, but in lowest terms.
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
Answer:
y=-2x+17
Step-by-step explanation:
The following best describes a basic postulate of the Euclidean geometry
Option first - All lines continue indefinitely.
One of the postulates of the Euclidean geometry states that any straight line segment can be extended indefinitely in a straight line. So according to this postulate, the first one is correct.
Sequence are sets of numbers that follow a pattern or a rule.
