Answer
Notebook each =$4
Folder each = $9
First we write out what we know
Notebook = n
Folder = f
It says a notebook is +5 than a folder so
f = n +5
It says he bought 3 notebooks and 2 folders for $30
3n + 2f = 30
Because we know from the first equation
f=n+5, we can substitute that into the second equation for f
3n + 2(n+5) = 30
3n + 2n +10 =30. Now Combine like terms
5n +10 =30. Now isolate n by subtracting 10 from both sides
5n = 20. Now isolate n by dividing both sides by 5
n = 4
Now we do the same thing to find f
We substitute the value of n (4) into the equation 3n + 2f =30
3(4) +2f =30
12 +2f =30. Now isolate f by subtracting 12 from both sides
2f = 18. Now isolate f by dividing both sides by 2
f = 9
We check our work by inserting the n and f values we found into one of the equations
n + 5 = f
4 + 5 = 9
9 = 9. It worked it equals so it’s correct
To solve a problem like this, we need to start with the innermost parenthesis. Doing that, we get to 4+1, evaluating it giving us 5. This turns our expression into 5 x {3 x [9 - 5]} + 20 ÷ 4 x 2.
Now, the innermost parenthesis is 9-5. Evaluating that gives us 4. Our expression is now 5 x {3 x 4} + 20 ÷ 4 x 2.
Once again, we go to the innermost parenthesis and evaluate whatever is there. This turns our expression into <span>5 x 12 + 20 ÷ 4 x 2.
Now, we can simply use order of operations to compute that the value of the expression is equal to 70. </span>
The median is 1.5, hope this was helpful :)
Answer:yes
Step-by-step explanation:
Answer:
The solution can be defined as follows:
Step-by-step explanation:
They also have a significant outcome in our instance. Its value of F is 1.773, with such a p-value of 0.212 achieved meaning (which is greater than the .05 alpha level). It means that the press with different levels of stress of the stress variable may not differentiate objectively.
Even so, we still do not know which one of the multiple mechanisms is significant. They realize the diff. To do just that, the results of the Tukey HSD test should be regarded.
HSD Tukey
Looking at the Multiple Correlations table below, you will see that mean values were created for the standard deviation among pairs of various stress varying concentrations (High - Low; High - Medium )
This can be seen on one-way ANOVA(1.773, p=.212), there's no statistically significant difference between the groups. A Tukey post hoc study has observed that the increase among medium and high stress is statistically significant, as well as the difference among low, medium, and high stress is important.
