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ZanzabumX [31]
3 years ago
5

2.0Plss solve for x...........................

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

x = - 7

Step-by-step explanation:

( x + 139 ) and 132 are vertically opposite angles.

Vertically opposite angles are equal,

x + 139 = 132

x = 132 - 139

x = - 7

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Rotation 180° counterclockwise around the origin of the point (4, -1)
Colt1911 [192]
(-4,1) is the answer
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Write an expressionNick has x toy race cars. This is one third of what Bob has. How many toy race cars does Bob have?
natita [175]

Given:

Nick has x toy race cars. This is one-third of what Bob has.

So, the number of Nick toys = one-third of what Bob has.

Let the Bob has y toys

So, we can write the following expression:

x=\frac{1}{3}y

Solve for y, multiply both sides by (3):

y=3x

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Bob has (3x) toy race cars.

3 0
1 year ago
FInd the mean, median, mode for the following data:
Anettt [7]

Answer:

Mean : 16

Median: 15.5

Mode: 16

Step-by-step explanation:

<u><em>Given/To Find:</em></u>

<em>Find the mean, median, mode for the following data:</em>

<em>10, 10, 12, 13, 13, 14, 15, 16, 16, 16, 18, 22, 23, 26</em>

<u><em>Solve:</em></u>

<em>Mean: Average</em>

<em>Formula: Adding all number in data then divide by  the total number in data.</em>

<em>10 + 10 + 12 + 13 + 13 + 14 + 15 + 16 + 16 + 16 + 18 + 22 + 23 + 26 = 224</em>

<em>224/14 = 16</em>

<em>Median: Middle Number</em>

<em>Formula: Number in the middle</em>

<em>10,</em><em> 10, 12, 13, 13, 14, 15, 16, 16, 16, 18, 22, 23,</em><em> 26</em>

<em>10, 10,</em><em> 12, 13, 13, 14, 15, 16, 16, 16, 18, 22, </em><em>23, 26</em>

<em>10, 10, 12,</em><em> 13, 13, 14, 15, 16, 16, 16, 18, </em><em>22, 23, 26</em>

<em>10, 10, 12, 13,</em><em> 13, 14, 15, 16, 16, 16, </em><em>18, 22, 23, 26</em>

<em>10, 10, 12, 13, 13, </em><em>14, 15, 16, 16, </em><em>16, 18, 22, 23, 26</em>

<em>10, 10, 12, 13, 13, 14, </em><em>15, 16, </em><em>16, 16, 18, 22, 23, 26</em>

<em>15 + 16 = 31</em>

<em>31/2 = 15.5</em>

<em>Mode: Most often number: 16</em>

<u><em>Kavinsky</em></u>

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3 years ago
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