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pishuonlain [190]
3 years ago
14

Which of the following theorems states that when the chords intersect wih each other inside the circle the products of their seg

ments are equal
A. Two intersecting chords
B. Secant-secant segments
C. Tangent - secant segments
D. Two intersecting secant
​
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

Two intersecting chords is the correct answer

thank you

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Which fraction represents the probalility of a likely event
podryga [215]

Answer:

D.) \frac{3}{4}

I hope this helps!

7 0
3 years ago
..........................
liubo4ka [24]

Answer:

82.96

Step-by-step explanation:

area of box:

A = L^2 = (14 in.)^2 = 196 in.^2

area of pizza:

A = (pi)r^2 = 3.14 * (6 in.)^2 = 113.04 in.^2

Empty area:

196 in.^2 - 113.04 in.^2 = 82.96 in.^2

7 0
3 years ago
Find y’ for y=7sec^3x
laiz [17]
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.

We then multiply everything together to simplify:

sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes

3x^2 * sin(x^3)/(cos(x^3))^2

and multiplying the constant 7 from the beginning:

7 * 3x^2 = 21x^2, so...

our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2


6 0
3 years ago
Identify the slope and y-intercept. If the equation is in standard form, you may need to switch it to slope-intercept form. Sket
malfutka [58]

Answer:

the slope is -4/5 and the y-intercept is 0

Step-by-step explanation:

3 0
3 years ago
What are the zeros of the function f(x) = x2 + 8x +4, expressed in simplest radical form?
Elanso [62]

Answer:

x = - 4 ± 2\sqrt{3}

Step-by-step explanation:

Given

f(x) = x² + 8x + 4

To find the zeros let f(x) = 0, that is

x² + 8x + 4 = 0 ( subtract 4 from both sides )

x² + 8x = - 4

To solve using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(4)x + 16 = - 4 + 16

(x + 4)² = 12 ( take the square root of both sides )

x + 4 = ± \sqrt{12} = ± 2\sqrt{3} ( subtract 4 from both sides )

x = - 4 ± 2\sqrt{3}

Thus the zeros are

x = - 4 - 2\sqrt{3} and x = - 4 + 2\sqrt{3}

5 0
3 years ago
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