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GREYUIT [131]
2 years ago
8

How would you do this

Mathematics
1 answer:
Keith_Richards [23]2 years ago
8 0

22Answer:

Step-by-step explanation:

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What is 4x+5 less than or equallys too 13 equals
gizmo_the_mogwai [7]
If you are trying to solve for x, then 
4x+5<=13
 subtract both sides by 5

4x<=8
then divide both sides by 4 
x<=2
5 0
4 years ago
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8th grade math help asap??
wel
Show more of the pic because I cant see the options for what to choose.
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3 years ago
A line that includes the point (-3,-4) and (-4,f ) has a slope of 6. What is the value of f?
Eduardwww [97]

Answer:

f = -10

( -3, -4) ( - 4 , -10)

Step-by-step explanation:

Formula for slope

m =( y_2 - y_1)/(x _2 - x _1)

m = 6

6 = (y_2 - y_1) / (x _2 - x_1)

Substitute the points

( -3 , -4) ( -4 , f)

x_1 = -3

y_1 = -4

x_2 = -4

y_2 = f

Insert the values into

6 = (y_2 - y_1) / (x_2 - x_1)

6 = (f - (-4))/ ( -4 - (-3)

6 = ( f + 4)/ ( -4 + 3)

Cross multiply

6 ( -4 + 3) = f + 4

6 ( -1) = f + 4

-6 = f + 4

-6 - 4 = f

f = -6 - 4

f = -10

( -3 , -4) ( -3 , f)

The value of f is -10

( -3 , -4) ( -3 , -10)

8 0
4 years ago
There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral
leva [86]

Answer:

The answer is "\sqrt{12.5}"

Step-by-step explanation:

\to (3,2),  \ (6,1)

Distance=\sqrt{9+1}=\sqrt{10}

midpoint height =\sqrt{10+2.5}=\sqrt{12.5}

let

Gradient = \frac{1}{-3}      

Perpendicular Gradient= 3

midpoints = (4.5, 1.5)

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle(4.5,1.5) radius will be\sqrt{12.5}.

5 0
3 years ago
Explain how you use a quick picture to find the quotient and remainder
Varvara68 [4.7K]
Example question: There are 38 students in a baseball club. The coach needs to split them up into equal groups of 4. How many groups can be made? How many kids are left over?
Answer: You would make groups of 4 to get your quotient (9). Then whatever is NOT in a group is your left over.
8 0
4 years ago
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