Splitting up the interval of integration into 
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length 
. The right endpoints of each subinterval follow the sequence
with 
. Then the left-endpoint Riemann sum that approximates the definite integral is
and taking the limit as 
gives the area exactly. We have
The answer for this question is 4.
Mikayla subtracted 4 from both sides in the beginning when she should've added it to both sides to cancel it out on the right. the correct answer should actually be x=1
Answer:
The answer is A
Step-by-step explanation:
The graph slanted from left to right.
4x + 2y = 8
-4x
2y=8-4x
divide the equation by 2 since you only need on y. -2x+8 =y
it's a negative x so the graph would be from upper left to lower right.
