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babymother [125]
2 years ago
14

Cobly has 20 jars if he buys 5 more how many jars would he have

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
8 0

Colby would have 25 jars

20 + 5 = 25

You're welcome ;)

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I need Your help Plish✍​<br>(brainliest)
Anit [1.1K]

Answer:

1/5 2/5

Step-by-step explanation:

There is 5 zones meaning its 1 out of 5.

If you flip twice its double your chance.

Hope This Helps

6 0
4 years ago
What is the solution to 2x+12=5x-9
Wittaler [7]
So 2x+12=5x-9
you want all of the unknowns on one side and all of  the known values on the other or
subtract 2x from both sides
12=3x-9
add 9 to both sides
21=3x
divide both sides by 3
7=x
4 0
3 years ago
Read 2 more answers
Check my answers please?
sukhopar [10]
1. Correct answer is a (since when you are not given the n values, it is implied that the first value is 1). 
3. Correct answer is a (a(n)=-3+4(1-1)=-3).
 7. The pattern is to reduce the previous value by 4, thus the 12th term of the sequence is -24 (a(n)=20 - 4(n-1)=20 - 4(12-1)=-24).
 8. Missing term is 26 (32+20=52; 52/2=26).
 10. Pattern is 625/1=625; 625/5=125; 125/5=25; 25/5=5, thus. the 10th term is 1/3125 (answer a).
5 0
3 years ago
Joshua has a bag of marbles. In the bag are 5 white marbles, 3 blue marbles, and 7 green marbles. Peter randomly draws one marbl
Step2247 [10]

Answer:

1 / 5

Step-by-step explanation:

Given that:

Number of white marbles = 5

Number of blue marbles = 3

Number of green marbles = 7

Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :

Probability = required outcome / Total possible outcomes

Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles

First draw:

P(Green) = 7 / 15

Second draw:

Required outcome = 7 - 1 = 6

Possible outcomes = 15 - 1 = 14

P(green) = 6 / 14

Probability of drawing out two green marbles :

(7/15 * 6/14) = 42 / 210 = 1 / 5

6 0
3 years ago
Please help will mark brainliest
beks73 [17]

Answer:

m\angle N=57^{\circ}

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares LM\cong LN, the remaining unknown angles are equal (m\angle N=m\angle M). The sum of the interior angles of a triangle always add up to 180^{\circ}$.

Therefore:

m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$} .

7 0
3 years ago
Read 2 more answers
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