HELP PLS PLS PLS PLS PLS z
1 answer:
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Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then ≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2± where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704± ≈ -0.171 ±0.237 that is (−0.408, 0.066)
Answer:
2x + 3y ≥ 5
Step-by-step explanation:
See the graph attached.
The bold straight line passes through the points (1,1) and (4,-1).
Therefore, the equation of the straight line will be
⇒ 3(y + 1) = - 2(x - 4)
⇒ 3y + 3 = - 2x + 8
⇒ 2x + 3y = 5 ............. (1)
Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).
So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5
Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)
Start with the original expression.
Use the Distributive Property — multiply by both
and
.
Combine the like terms — add up all the constants.
Reorder the terms.