Question

Please Help ASAP with Math

Answer 1

Answer:

5.33

Step-by-step explanation:

move the 4 out of the summation because  just a constant multiplier

4 *sum from 1 to 10 for (1/4)^(n-1)   [sorry i don't know how to write sums using latex)

The formula for the geometric sum is :

First term*(1-multiplier^n)/(1-multiplier), formally $\frac{a_1(1-r^n)}{1-r}$

Here multiplier is 1/4

First term is (1/4)^(1-1) = 1

Thus the value of sum is $1*(1-(1/4)^1^0)/(1-1/4)$which equals $(1- (1/4)^1^0)*4/3$

We factored out 4 so its $4*(1-(1/4)^1^0)*4/3$ which is $16/3 * (1- (1/4)^1^0)$

This equals 5.333328247 which is 5.33 to the nearest hundredth