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stiv31 [10]
2 years ago
14

Please Help ASAP with Math

Mathematics
1 answer:
vampirchik [111]2 years ago
5 0

Answer:

5.33

Step-by-step explanation:

move the 4 out of the summation because  just a constant multiplier

4 *sum from 1 to 10 for (1/4)^(n-1)   [sorry i don't know how to write sums using latex)

The formula for the geometric sum is :

First term*(1-multiplier^n)/(1-multiplier), formally \frac{a_1(1-r^n)}{1-r}

Here multiplier is 1/4

First term is (1/4)^(1-1) = 1

Thus the value of sum is 1*(1-(1/4)^1^0)/(1-1/4)which equals (1- (1/4)^1^0)*4/3

We factored out 4 so its 4*(1-(1/4)^1^0)*4/3 which is 16/3 * (1- (1/4)^1^0)

This equals 5.333328247 which is 5.33 to the nearest hundredth

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