Let x represent the number of hours he worked during the weekdays (not Saturday or Sunday).
If x is how much he worked on the weekdays and he worked 5 times as much on Sat and Sun, then hopefully you agree that on Sat and Sun he worked 5x hours.
So we have 5x hours on the weekends and x hours on the weekdays, so in total for the whole week we have 5x + x = 6x hours in total.
The question tells us that he worked 30 hours total, so 6x = 30
Divide both sides by 6 to isolate x and we have x = 5.
He worked 5 hours the rest of the week.
Hope this helps. If it does, please be sure to make this the brainliest answer! :)
Answer: y= -3(x+4)
Step-by-step explanation:
sin(2x) = cos(x)
2sin(x)cos(x) = cos(x) Expand sin(2x).
2cos(x) 2cos(x) Divide 2cos(x) on each side.
sin(x) = ¹/₂
sin⁻¹[sin(x)] = sin⁻¹(¹/₂) Use sin⁻¹(x) on each side.
x = 30, 150 Find the answer.
(x^2-5x-6)= (x+1)(x-6)
one of them has to be zero...
x=-1, x=6.
Hope this helps!
