A female mouse is trying to decide if she will leave her natal nest to reproduce alone. If she leaves, she will be able to produ
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Answer: In this type of cross between MmDdPp and mmddpp, the phenotypic ratios in the eight possible phenotypes are as follow; a. solid, normal, smooth = 1:8
b. solid, normal, peach = 1:8
c. solid, dwarf, smooth = 1:8
d. solid, dwarf, peach = 1:8
e. mottled, normal, smooth = 1:8
f. mottled, normal, peach = 1:8
g. mottled, dwarf, smooth = 1:8
h. mottled, dwarf, peach = 1:8
Explanation: The number of gametes that can be formed from a particular genotype is given as 2^n where n is the number of heterozygous loci. In the genotype MmDdPp, n = 3. Therefore, 8 gametes can be formed.
In genotype mmddpp, n = 0. Therefore, only one type of gamete can be formed.
Crossing the two genotype (MmDdPp and mmddpp) as shown in the attached image, 8 possible offsprings can be achieved. Phenotypes of these offspring had been stated earlier. The phenotypic frequency of each of these offspring is one out of eight (⅛).
