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xxTIMURxx [149]
2 years ago
6

What is this expression in simplest form?

Mathematics
1 answer:
gayaneshka [121]2 years ago
8 0

Answer:

A. 1÷(X+1) (x-2)

some steps are directly

tag me in brainlist if you like it

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Can someone pls help me with this?
Misha Larkins [42]

Answer:

the answer is C

Step-by-step explanation:

3 0
2 years ago
Help me please with this math question! giving brainliest to the correct answer
Arlecino [84]

Answer:

12.5

Step-by-step explanation:

All I really did was divide the circumference by pi to get the diameter which you end up dividing it by two to get the radius.

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2 years ago
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What is 16,500rounded to the nearest ten thousand
harina [27]
Well just think, what is the ten thousands place? 1 right by 6. From this to round you look at the previous number 6, anything 5 or above will be rounded up making the 1 into a 2, anything lower than a 5 will become rounded down making the 1 stay the same, but instead making it into 10,000
So the answer would be 20,000
5 0
3 years ago
A consulting firm submitted a bid for a large research project. The firm's management initially felt they had a 50-50 chance of
Verizon [17]

Answer:

Probability = 0.50

Step-by-step explanation:

Given

Probability = 50\ 50\ chance  

Successful\ Bids = 80\%

Unsuccessful\ Bids = 35\%

Required

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In this case, we only consider the 50 50 chance probability

Probability = \frac{50}{50 + 50}

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5 0
3 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
2 years ago
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