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2 years ago

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!

Mathematics

2 answers:

nirvana33 [79]2 years ago

7 0

To see if a table of values represents a linear function, check to see if there’s a constant rate of change. For example, if there is you’re look at a linear function. Depending on how it increases and decreases

Lubov Fominskaja [6]2 years ago

5 0

Answer:

It looks like a curve in a graph and has a variable slope value. The major difference between linear and nonlinear equations is given here for the students to understand it in a more natural way

Step-by-step explanation:

You might be interested in

I dont know how to do this,can someone please help me?

MakcuM [25]

So this problem is asking you to plug numbers in for t. 0 1 2 3 4 5. So your first equation would be 2× 0+8 and you would get 8 so for 0 toppings you would pay 8 dollars then graph this over 0 up 8. Next equation 2×1+8 is 10. Graph. over 1 up 10. Next 2×2+8 is 12. Graph. Over 2 up 12. next 2× 3 + 8 is 14. Graph. Over 3 up 14. Next 2×4+8 is 16 so over 4 up 16. Last 2×5+8 is 18 so over 5 up 18. Your Y-intercept is the dot that is on the y axis and in this problem that is 8. This means if you buy 0 toppings you will spend 8 dollars.

5 0

3 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

2 years ago

Find ratios equivalent to the ratio described in the situation 1 to 6

katrin2010 [14]

2/12, 4/24, 3/18, 5/30 etc.

4 0

2 years ago

Expand to write an equivalent expression -1/2 (-6x+8y) (Pleasee help i need an answer rqqqq)

Alik [6]

Answer:

$- \frac{1}{2} ( - 6x + 8y) \\ = \frac{1}{2} (6x - 8y) \\ = 3x - 4y$

6 0

3 years ago

You are standing 6 feet away from the stage and your friend is standing 7 feet away from the stage. You are standing on a platfo

coldgirl [10]

Answer:

The distance from your eyes to the stage is 8.85 ft

Step-by-step explanation:

Your distance to the stage is 6 feet

Your eyes are 6.5 feet tall

You need to find the distance of your eyes towards the stage.

This situation can be modeled using a rectangle triangle, where the adjacent side x is the horizontal distance to the stage and the opposite side h is the vertical distance of your eyes to the stage.

Observe the attached image.

Then, we look for the distance z from your eyes to the stage. This distance is the hypotenuse of the right triangle.

So, using the Pythagorean theorem we have:

$z ^ 2 = h ^ 2 + x ^ 2\\\\z = \sqrt{h^2 +x^2}$

Where

$h = 6.5\ ft\\\\x = 6\ ft$

therefore:

$z = \sqrt{(6.5)^2 +(6)^2}\\\\z =8.85\ ft$

4 0

2 years ago