Ok so R=alfonso's rate
w=wind rate=4
d=rt
with wind rate is R+4
agaoins wind rate is R-4
with wind distance is 34
against is 18 miles
time is same
34=(r+4)t
18=(r-4)t
34=(r+4)t
divide both sides by (r+4)
34/(r+4)=t
18=(r-4)t
divide both sides by (r-4)
18/(r-4)=t
18/(r-4)=t
34/(r+4)=t
set equal to each other
18/(r-4)=34/(r+4)
multiply both sides by (r-4)(r+4)
18(r+4)=34(r-4)
distribute
18r+72=34r-136
subtract 18r from both sides
72=16r-136
add 136 to both sides
208=16r
divide both sides by 16
13mph
answer is 13mph with no wind
To solve this problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the exercise above:
2x²−6x+1=0
2. The quadratic equation is:
x=[-b±√(b²-4ac)]/2a
Where:
a=2
b=-6
c=1
3. When you substitute these values into the quadratic equation, you obtain:
x=3/2-√(7)/2
x=3/2+√(7)/2
Answer:
x = 3
Step-by-step explanation:
3(2 - 4x) = -30
=>6 - 12x = -30
=> 12x = 36
=> x = 3
Remark
The five is after the decimal point. The 10 in that form is tenths. It represents a number in the denominator. So you would write it as 5/10 and say it as 5 tenths.
The answer is D.
