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3 years ago

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Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Divide each number by 4 to find 3

allsm [11]3 years ago

4 0

Answer:

Step-by-step explanation:

just divide each number by 4 to figure out how many for 3

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With the trend on this scatter plot, how many hours per week would a level-9 gymnast practice?

Vsevolod [243]

I think that it would be C

6 0

3 years ago

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Who is most likely to get a good credit card rate based on their credit-to-debt ratio?

aksik [14]

Laurel has a less credit-to-debt ratio compared to others so Laurel is most likely to get a good credit card rate option (B) is correct.

It is defined as the amount one party needs to pay to another party as the first party borrowed an amount that will be credited by the second party. Debt occurs when one party cannot be able to purchase something under normal circumstances.

We have a statement:

Who is most likely to get a good credit card rate based on their credit-to-debt ratio?

As we know,

Credit-to-debt ratio = Credit card balance ÷ Credit limit

A. Darius has a credit limit of $6,000 and a balance of $1,200.

Credit-to-debt ratio = 1200/6000 = 0.2 or 20%

B. Laurel has a credit limit of $5,000 and a balance of $500.

Credit-to-debt ratio = 500/5000 = 0.1 or 10%

C. Lenore has a credit limit of $10,000 and a balance of $3,500.

Credit-to-debt ratio = 3500/10000 = 0.5 or 35%

D. August has a credit limit of $2,000 and a balance of $300.

Credit-to-debt ratio = 0.15 or 15%

As we can see Laurel has a less credit-to-debt ratio compared to others so Laurel is most likely to get a good credit card rate.

Thus, Laurel has a less credit-to-debt ratio compared to others so Laurel is most likely to get a good credit card rate option (B) is correct.

Learn more about the debt here:

brainly.com/question/17286021

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6 0

2 years ago

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Suppose the survey was based on a sample of 700 companies. Find the 80% confidence interval for the proportion of all companies

Angelina_Jolie [31]

Answer:

$0.61 - 1.28\sqrt{\frac{0.61(1-0.61)}{700}}=0.586$

$0.61 + 1.28\sqrt{\frac{0.61(1-0.61)}{700}}=0.634$

The 80% confidence interval would be given by (0.586;0.634)

Step-by-step explanation:

A recent survey showed that 61% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 700 companies. Find the 80% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.2$ and $\alpha/2 =0.1$ . And the critical value would be given by: