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3 years ago

What is the area when radius=2.6in

Mathematics

1 answer:

fomenos3 years ago

7 0

Answer:

Hope this helps!

Step-by-step explanation:

Area = π · r2 = 3.14 · 2.62 = 21.24 square inches.

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Need help , can someone help me?

oksian1 [2.3K]

The answer is B.

Step-by-step explanation:

The min and max are 6 and 30, which is the same for all of the choices.

We need to find the median, which since there's an even number of elements we take the mean of the two elements in the middle (eg 20 and 22), which gives us 21. So the middle whisker will be on 21, so we know the answer is B or D.

Next, we need to find the upper and lower quartile. For these, we take the median again, but this time it's the median of the upper and lower halves (split by our median of 21). So, for the lower half, we have 6, 7, 9, 9, and 20. Since there's an odd number of elements this time, we just take the middle element, which is 9, so that's the lower whisker.

Then we do the same for the upper quartile. The upper half (above 21) is 22, 26, 28, 29, and 30. Since the number of elements is odd again, we just take the middle element, which is 28, so that is the upper whisker.

Plot the lower and upper whiskers and the median and you get graph B.

3 0

3 years ago

Read 2 more answers

A rectangular playground is surrounded by a chain link fence that costs $2 per linear foot on three sides and a fancier wooden f

NARA [144]

Answer:

31.6 feet by 15.8 feet.

Step-by-step explanation:

Area of a Rectangle = Length X Breadth = LB

The area of the playground is to be 500 square feet

Therefore:

LB=500

Perimeter of the Rectangle = 2(L+B)

The Chain link fence that costs $2 per linear foot on three sides and a fancier wooden fence that costs $6 per linear foot on the fourth side.

Cost = ${2(L+2B)+6L}=2L+4B+6L=8L+4B

Cost= $(8L+4B)

From: LB=500, B=500/L

Substitute B into 8L+4B

C(L) = $8L+4(\frac{500}{L} )=8L+\frac{2000}{L} =\frac{8L^2+2000}{L}$

C(L)= $\frac{8L^2+2000}{L}$

The minimum cost of the fencing occurs when the dimensions are minimum.

If we take the derivative of C(L)

$C^{'}(L)=\frac{8L^2-2000}{L^2}$

At $C^{'}(L)=0$

$\frac{8L^2-2000}{L^2}=0\\8L^2-2000=0\\8L^2=2000\\L^2=250\\L=15.8 ft$

Recall: B=500/L

$B=\frac{500}{15.8}=31.6 ft$

The dimensions that minimizes the total cost of the fencing are 31.6 feet by 15.8 feet.

4 0

4 years ago

The cost to join a gym includes a one-time membership fee, plus a monthly fee. John joined the gym and paid $325 for 6 months.Ab

Anettt [7]

We need to construct the system of equations in order to solve that problem. Let's denote one-time membership fee with x and monthly fee with y. Then we can write that John paid x+6y=325 and Abigail paid x+9y=475. Solving the system of equations $\left \{ {{x+6y=325} \atop {x+9y=475}} \right.$ , we find that x=25 and y=50. The monthly fee is 50 dollars.

8 0

3 years ago

Help help help help help

Doss [256]

Answer:

the answer is c

Step-by-step explanation:

x - 7, y + 6

- 1 - 7, 4 + 6

- 8, 10

8 0

3 years ago

Read 2 more answers

Express answer in exact form. Show all work for full credit.

Gennadij [26K]

Answer:

Area segment = 3/2 π - (9/4)√3 units²

Step-by-step explanation:

∵ The hexagon is regular, then it is formed by 6 equilateral Δ

∵ Area segment = area sector - area Δ

∵ Area sector = (Ф/360) × πr²

∵ Ф = 60° ⇒ central angle of the sector

∵ r = 3

∴ Area sector = (60/360) × (3)² × π = 3/2 π

∵ Area equilateral Δ = 1/4 s²√3

∵ The length of the side of the Δ = 3

∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3

∴ Area segment = 3/2 π - (9/4)√3 units²

4 0

3 years ago