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kiruha [24]
2 years ago
15

1 decigram (dg) = ______ grams (g)?

Mathematics
1 answer:
AleksandrR [38]2 years ago
6 0

Answer:

B) 0.1

Step-by-step explanation:

The prefix "deci-" means "tenth", so a decigram would be one-tenth of a gram (or 0.1 grams). Therefore, option B is correct.

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Line segment AB is reflected across the y–axis to form line segment CD. Then, line segment CD is rotated 90° clockwise about the
Maksim231197 [3]

Answer:

The coordinates of EF are E(5,-4) and F(1,-4).

The line segment EF is in QIV

Step-by-step explanation:

The line segment AB has vertices at: A(-4,5) and B(-4,1).

We apply the rule (x,y)\to (-x,y) to reflect AB in the y-axis to obtain CD.

\implies A(-4,5)\to C(4,5)

\implies B(-4,1)\to D(4,1)

We apply the rule (x,y)\to (y,-x) to rotate CD 90 degrees clockwise about the origin to obtain EF.

\implies C(4,5)\to E(5,-4)

\implies D(4,1)\to F(1,-4)

The coordinates of EF are E(5,-4) and F(1,-4).

See attachment

4 0
4 years ago
What is the product of (x-2)(x-6)? *
belka [17]

Answer:

x^2-4x+12

Step-by-step explanation:

(x-2)(x-6)

x(x-6)-2(x-6)

x^2-6x-2x+12

x^2-4x+12

7 0
3 years ago
Read 2 more answers
The set of data in the table below represents a linear function.
Vinil7 [7]

Answer:

y = 2x - 19

Step-by-step explanation:

Graph the points on the table and you'll be able to see the answer. That's how I went about it.

or use m = y^2 - y^1 divided by x^2 - x^1 to find the slope, then solve for the initial value from there

8 0
1 year ago
Solve question 20 (a) and (b)<br>​
RUDIKE [14]

Answer:

You first have to read on the coordinates where the curve and the straight line meet or cuts across

a.) 53

b.) 13

5 0
3 years ago
PLEASE HELP
Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

please mark brainliest

4 0
2 years ago
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