<span>17 1/3 + (-50 1/3) -5 1/2
= -33 - 5 1/2
= (</span>-33 ) + ( - 5 1/2)
<span>= -38 1/2
</span>
7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
Answer:
3x+15= 4x-10
3x-4x= -10-15
-x= -25(minus will be cut on both sides)
so x= 25
8 inches. 3/4 of 8 feet is 6 feet leaving two left over, one third of that is 8 inches.
Answer:
2839.4 meters
Step-by-step explanation:
Given that:
Altitude = 1200 m
Using trigonometry :
The distance from point P to the airplane :
Using trigonometric relation :
Sin θ = opposite / hypotenus
Sin θ = altitude / x
Sin θ = 1200 m / x
Sin 25 = 1200 / x
0.4226182 = 1200 / x
x = 1200 / 0.4226182
x = 2839.4423
Distance from P to airplane = 2839.4 meters
