Ask question

Ask question

All categories

2 years ago

11

Please help me on 1-107

1 answer:

Ksenya-84 [330]2 years ago

3 0

A is 25
B is 45
C is 30

You might be interested in

Solve for y 3x-4y=10

Georgia [21]

3x-4y=10

or,4y=3x-10
or,y=(3x-10)/4

so,y=3/4 x-5/2

5 0

2 years ago

Read 2 more answers

The video streaming service that you want to use is represented with the equation below, where y represents the the total monthl

Dominik [7]

Answer:

It’s 11.25

Step-by-step explanation:

6 0

2 years ago

Select the correct answer.<br> What is 22% of 50?<br> Α.44<br> B.28<br> C.22<br> D. 11

Damm [24]

The answer should be D. 11?

7 0

2 years ago

Read 2 more answers

While picking thirty apples, Mia noticed that six apples had worm holes and had to be thrown away. What is the ratio of good app

sergejj [24]

6:24 or and 6/24

this explains the ration of the good apples and the bad apples

3 0

2 years ago

Read 2 more answers

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

3 years ago