Answer:
any equation that has the same slope as the original line (3/5x)
Step-by-step explanation:
examples:
y= 3/5x + 5
y= 3/5x - 3
9514 1404 393
Answer:
Step-by-step explanation:
Let J and M represent the current ages of Jacob and his Mother.
<u>currently</u>:
M = 3 +9J
<u>in 11 years</u>:
M+11 = 5 +3(J+11)
Using the first equation to substitute for M in the second, we have ...
(3 +9J) +11 = 5 +3(J +11) . . . . . substitute for M
9J +14 = 3J +38 . . . . . . simplify
6J + 24 . . . . . . . . . . subtract 3J+14
J = 4 . . . . . . . . . . divide by 6
M = 3 +9(4) = 39
Jacob is 4 and his mother is 39.
Answer:
27°C
Step-by-step explanation:
The temperature on February 9th 1934 = -15°C
The next day the temperature rose 42 degrees.
We need to find an expression for the temperature on February 10th.
February 10th temperature = -15 + 42
= 27°C
So, the temperature on February 10th is 27°C.
Invested amount (P) = $300.
Time in years (t) = 2 years.
Balance after 2 years (A) = $329.49.
Let us assume rate of interest = r % compounds annually.
We know, formula for compound interest
Plugging values in formula, we get
Taking square root on both sides, we get
r=0.048.
Converting it into percentage by multiplying by 100.
r=0.048 × 100
r = 4.8 %
Therefore, the rate of interest on the account is 4.8% compounds annually.
Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
