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expeople1 [14]
3 years ago
11

PLEASE HELP BRAINLIEST TO FIRST ANSWER MIDDLE SCHOOL MATH

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0

Answer:

2nd row: 55 pirates

3rd row: 121 pirates

Step-by-step explanation:

The unit rate is 11:1 or 11 pirates for every 1 ship.

Using this info, you can create equivalent rations for every 5 ships and 11 ships.

Number of pirates for 5 ships:

Multiply 11 by 5 to create and equivalent ratio of 11:1.

11 x 5 = 55 pirates

Number of pirates for 11 ships:

Multiply 11 by 11 to create and equivalent ratio of 11:1.

11 x 11 = 121 pirates

Veronika [31]3 years ago
5 0

Answer:

Number of pirates :- 22 44 66.

Number of ships :- 2 4 6 .

Step-by-step explanation:

Yw

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The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4. Work out the value of k.
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The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.

Gradient is the slope

So the slope of the line joining the points A(3,-5) and B(6,k) is 4

Slope of line joining two points = \frac{y_2-y_1}{x_2-x_1}

A(3,-5) and B(6,k) are (x1,y1)  and (x2,y2)

slope = \frac{y_2-y_1}{x_2-x_1}

slope = \frac{k-(-5)}{6-3}=\frac{k+5)}{3}

We know slope =4

 \frac{k+5)}{3}=4

Cross multiply  and solve for k

k + 5 = 12

k = 7

The value of k = 7

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A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}
&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\
&------&------&------\\
\textit{pure water}&x&0.00&0x\\
\textit{6\% solution}&5&0.06&0.3\\
-----&------&------&------\\
mixture&y&0.04&0.04y
\end{array}
\\\\\\
\begin{cases}
x+5=\boxed{y}\\
0x+0.3=0.04y\\
---------\\
0.3=0.04\left( \boxed{x+5} \right)
\end{cases}
\\\\\\
0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
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