Solution to the system y=-x2-3x+2 y=x+6

1 answer:

8 0

Answer:

$x=-2,y=4$

Step-by-step explanation:

$y=-x^2-3x+2$

$y=x+6$

$x+6=-x^2-3x+2$

$x^2+x+6=-3x+2$

$x^2+4x+6=2$

$x^2+4x+4=0$

$(x+2)(x+2)=0$

$x=-2$

$y=(-2)+6=4$

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